4x^(2/3)-7x^(1/3)-2=0

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Solution for 4x^(2/3)-7x^(1/3)-2=0 equation: 


x in (-oo:+oo)

4*x^(2/3)-(7*x^(1/3))-2 = 0

4*x^(2/3)-7*x^(1/3)-2 = 0

t_1 = x^(1/3)

4*t_1^2-7*t_1^1-2 = 0

4*t_1^2-7*t_1-2 = 0

DELTA = (-7)^2-(-2*4*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+7)/(2*4) or t_1 = (7-81^(1/2))/(2*4)

t_1 = 2 or t_1 = -1/4

t_1 = -1/4

x^(1/3)+1/4 = 0

1*x^(1/3) = -1/4 // : 1

x^(1/3) = -1/4

( -1/4 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 2

x^(1/3)-2 = 0

1*x^(1/3) = 2 // : 1

x^(1/3) = 2

x^(1/3) = 2 // ^ 3

x = 8

x = 8

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